(2-2y^2)/(y^2+5y-6)

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Solution for (2-2y^2)/(y^2+5y-6) equation:


D( y )

y^2+5*y-6 = 0

y^2+5*y-6 = 0

y^2+5*y-6 = 0

y^2+5*y-6 = 0

DELTA = 5^2-(-6*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)-5)/(1*2) or y = (-49^(1/2)-5)/(1*2)

y = 1 or y = -6

y in (-oo:-6) U (-6:1) U (1:+oo)

(2-(2*y^2))/(y^2+5*y-6) = 0

(2-2*y^2)/(y^2+5*y-6) = 0

y^2+5*y-6 = 0

y^2+5*y-6 = 0

DELTA = 5^2-(-6*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)-5)/(1*2) or y = (-49^(1/2)-5)/(1*2)

y = 1 or y = -6

(y+6)*(y-1) = 0

(2-2*y^2)/((y+6)*(y-1)) = 0

-2*y^2 = -2 // : -2

y^2 = 1

y^2 = 1 // ^ 1/2

abs(y) = 1

y = 1 or y = -1

y in { 1}

y = -1

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